12v^2+7v=0

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Solution for 12v^2+7v=0 equation: 



12v^2+7v=0

a = 12; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·12·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*12}=\frac{-14}{24}
=-7/12
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*12}=\frac{0}{24}
=0
$

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